西尾泰和のブログ

# tmp.py
x = 1
y = 2

def foo():
    x = 0
    print locals() #=> {'x': 0}
    execfile(r"c:\tmp.py", globals(), locals())
    print locals() #=> {'y': 2, 'x': 0}

    dic = {"x": 0}
    print dic #=> {'x': 0}
    execfile(r"c:\tmp.py", globals(), dic)
    print dic #=> {'y': 2, 'x': 1}

    del dic
    print locals() #=> {'y': 2, 'x': 0}
    locals()["x"] = 1
    locals()["z"] = 1
    print locals() #=> {'y': 2, 'x': 0, 'z': 1}
    
foo()

どちらかというとexecfileがというよりlocals()の返す辞書が不自然な挙動をしているような。

2.1 Built-in Functions

locals()
Update and return a dictionary representing the current local symbol table. Warning: The contents of this dictionary should not be modified; changes may not affect the values of local variables used by the interpreter.

localsの説明にちゃんと書いてあったけどもなぁ。